How can i solve this?

For a given rectangular matrix A, it is required to find the number of elements that exceed in absolute value the arithmetic mean of all elements of this matrix.

A=rand(3,4)

M=mean(mean(A))

A(:)

x=abs(M)

c=0

fori = length(ans)

if (ans(i)>abs(x))

c=c+1

end;

i did this. Is this even the solution of that question?im new to matlab

Answer 1

[David Hill]

a=mean(abs(A),'all');
s=sum(A>a,'all');

[David Hill]

Or,

a=mean(abs(A),'all');
s=nnz(A>a);

[David Hill]

Sorry, I misunderstood you. You want to take the mean first, then abs. Here is a one-liner that will work for you.

s=nnz(A>abs(mean(A,'all')));