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why the error occur when i use horzcat fuction

1 回表示 (過去 30 日間)
Shehab Tarek
Shehab Tarek 2020 年 5 月 27 日
閉鎖済み: MATLAB Answer Bot 2021 年 8 月 20 日
the error message
the output from y is matrix [2,3]
then i take only the first element
rr=4;
the output must be rr=[4,2,3]

回答 (1 件)

Geoff Hayes
Geoff Hayes 2020 年 5 月 27 日
Shehab - are you sure that the y is a 1x2 array like [2,3]? Or is it a 2x1 array like [2,3]'? If the latter, then you are trying to horizontally concatenate a 1x1 scalar with a 2x1 array and so the error makes sesne. From find, this function returns a vector with the same orientation as the input array. And your input at
y = find(a(iu) == matrix(:, i))
suggests that it is a column array/vector since you are comparing against the ith column of matrix. Use the MATLAB debugger to step through the code to validate this.
  1 件のコメント
Image Analyst
Image Analyst 2020 年 5 月 27 日
Before the horzcat line, put this
whos rr
whos y
What do you see in the command window? Do they both have the same number of rows?

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