How to cut a matrix

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smit g
smit g 2012 年 11 月 11 日
suppose I have a matrix [1 2 3 4 5; 6 7 8 9 0; 2 4 6 7 8]
now i want to cut and have the matrix [3 4 5; 8 9 0; 6 7 8] what should i do??
  4 件のコメント
Jan
Jan 2012 年 11 月 12 日
編集済み: Jan 2012 年 11 月 12 日
1000s of assignments in a few days?! This system does not allow to learn efficiently. Surely you will not remember anything you can answer now in 2 years (or to be exact: anything the forum can answer). Using the holidays to read the documentation is a bad idea also: The brain needs vacations for a general brush-up.
I'm not convinced, that your college is a good preparation for the real live in a scientific community. So I wish you the very best and good luck. Please let your children visit a different college.
Camilo Malagon-Nieto
Camilo Malagon-Nieto 2017 年 5 月 18 日
It is a valid question. I am using Matlab for quite some time and I just forgot how to do it. and I prefer to search here that go to the library, loan a MatLab book, look for the answer in the many chapters.... and so on.

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採用された回答

Wayne King
Wayne King 2012 年 11 月 11 日
編集済み: Wayne King 2012 年 11 月 11 日
Let
A = [1 2 3 4 5; 6 7 8 9 0; 2 4 6 7 8];
B = A(:,3:end);
  2 件のコメント
smit g
smit g 2012 年 11 月 11 日
thanks......
Wouter
Wouter 2017 年 5 月 15 日
This solution, though simple, forces matlab to copy all the remaining elements through the memory. Is there no more memory-friendly solution for large matrices to chop columns out of A without copying the remaining elements?

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