48 Dimensional Euclidean Distance.

Hi Guys, Hopefully this will be a quicky. If I have two points in two dimensional space I find the distance as:

 sqrt((x1-x2)^2 + (y1-y2)^2)

This is all good and well, but if I want the distance when each point has 48 (or otherwise) coordinates I don't really want to type out that equation. So is there some MatLab function which will let me pass it two arrays and find the resultant distance?

Thanks in advance,

Tim.

[Tim Mottram]

I have found the answer, Sorry, I was being silly.

 Distance = sqrt(sum((cords2-cords1).^2));

Answer 1

[Jan]

Most of all the components should not be stored in x1, y1, z1, ... but is vectors x1=[1 x 48], x2=[1 x48]. Then some alternatives:

x1 = rand(1, 48);
x2 = rand(1, 48);
x12 = x2 - x1;
Dist1 = sqrt(sum(x12 .^ 2))
Dist2 = sqrt(x12 * x12.')     % DOT product calculates the sum internally
Dist3 = norm(x12)