How to plot this picture use matlab?

 採用された回答

Steven Lord
Steven Lord 2020 年 5 月 21 日

0 投票

On the documentation page for the plot method of graph objects see the "Custom Graph Node Coordinates" example for how to plot nodes of your graph in specific locations.
The documentation page describing various types of customization you can do to a plotted graph may also be of use to you.

その他の回答 (1 件)

Ameer Hamza
Ameer Hamza 2020 年 5 月 20 日

1 投票

Try this code
s = randi([1 100], 1, 2000);
t = randi([1 100], 1, 2000);
G = graph(s, t);
p = plot(G, 'Layout', 'subspace');
p.NodeLabel = [];
p.MarkerSize = 10;
p.NodeCData = 1:100;
p.EdgeColor = [0.5 0.5 0.5];
colormap(autumn)
colorbar

5 件のコメント

z cy
z cy 2020 年 5 月 21 日
Thanks for your answer! I am so sorry not to express clearly. I need to plot two figures so that the situation becomes complicated.
The first figure is that each points need to fully connect with others. If the number of points is n, the connections of each points will be n-1.
The second figure is shown above all points only connect with extal serval anchor points. If the number of anchor points is m, the connections of points will be m.
I want to try use coordinate and adjacency matrix rather than not the connection relations to ensure the points are not changed.
Could you give me some suggestions? I am looking forward to your answer !
Ameer Hamza
Ameer Hamza 2020 年 5 月 21 日
Do you have the adjacency matrix for your graphs?
z cy
z cy 2020 年 5 月 21 日
I can calculate the anchor points.So, simply, if connected, set 1.
Ameer Hamza
Ameer Hamza 2020 年 5 月 21 日
編集済み: Ameer Hamza 2020 年 5 月 21 日
Do you have the code to create the adjacency matrix? Also, do you want to use custom coordinates for the node position?
z cy
z cy 2020 年 5 月 23 日
yes. Thank you!

サインインしてコメントする。

カテゴリ

ヘルプ センター および File ExchangeGraph and Network Algorithms についてさらに検索

製品

質問済み:

2020 年 5 月 20 日

コメント済み:

2020 年 5 月 23 日

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by