Distributing a cell array into another

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Jerki Jokne
Jerki Jokne 2020 年 5 月 18 日
回答済み: Star Strider 2020 年 5 月 18 日
If I have 2 cell arrays of chars, is it possible to distribute them such that they are combined and concatenated?
A = {'Category1', 'Category2'};
B = {'Mon', 'Tues', 'Wed', 'Thurs' 'Fri', 'Sat', 'Sun'};
Result = {'Category1 Mon', 'Category1 Tues', ..., 'Category1 Sun', 'Category2 Mon', 'Category2 Tues', ..., 'Category2 Sun'};

採用された回答

Star Strider
Star Strider 2020 年 5 月 18 日
Adding end spaces to each character array in ‘A’ and converting them to string arrays:
A = {'Category1 ', 'Category2 '};
B = {'Mon', 'Tues', 'Wed', 'Thurs' 'Fri', 'Sat', 'Sun'};
then transposing ‘A’ and adding them:
Result = string(A).' + string(B)
produces:
Result =
2×7 string array
Columns 1 through 4
"Category1 Mon" "Category1 Tues" "Category1 Wed" "Category1 Thurs"
"Category2 Mon" "Category2 Tues" "Category2 Wed" "Category2 Thurs"
Columns 5 through 7
"Category1 Fri" "Category1 Sat" "Category1 Sun"
"Category2 Fri" "Category2 Sat" "Category2 Sun"
Otherwise, the only option is likely two nested loops, concatenating elements of ‘A’ and ‘B’ in each iteration to form elements of ‘Result’.
.

その他の回答 (2 件)

the cyclist
the cyclist 2020 年 5 月 18 日
編集済み: the cyclist 2020 年 5 月 18 日
Here is a straightforward way:
A = {'Category1', 'Category2'};
B = {'Mon', 'Tues', 'Wed', 'Thurs' 'Fri', 'Sat', 'Sun'};
nA = numel(A);
nB = numel(B);
Result = cell(1,nA*nB);
nc = 0;
for ia = 1:nA
for ib = 1:nB
nc = nc + 1;
Result{nc} = [A{ia},' ',B{ib}];
end
end

Fangjun Jiang
Fangjun Jiang 2020 年 5 月 18 日
strcat(repmat(A,size(B')),repmat({' '},[length(B),length(A)]),repmat(B',size(A)))

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