Bessel function based equation returns NaN as output. Kindly check where I went wrong.
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I have attached the equation in image format and given the code below. Kindly help me find in which function i did mistake- bessel or sinh or exp.
EQUATION:
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/293871/image.jpeg)
CODE:
I1=@(x) besselj(1,x.*sqrt(i/j)).*besselj(1,x.*sqrt(j/i)).*besselj(0,x.*(s/(sqrt(i.*j)))).*((sinh(x.*(aw/i).*sqrt(i/j)))/(x.*(aw/i).*sqrt(i/j))).*((sinh(x.*(aw/j).*sqrt(j/i)))/(x.*(aw/j).*sqrt(j/i))).*(exp(-x.*(z/(sqrt(i.*j)))))
I=integral(I1,0,Inf)
M=pi*u*n1*n2*sqrt(i*j)*I
OUTPUT:
NaN
2 件のコメント
David Goodmanson
2020 年 5 月 19 日
Hi Swathi,
this is almost certainly happening because sinh(z)/z = 1 at z=0, but sinh(z) and z when calculated separately and divided, gives 0/0 =nan. You need to create a function that calculates sinh(z)/z and replaces nan by 1 at z=0.
Incidentally you are missing dots at a couple of locations:
((sinh(x.*(aw/i).*sqrt(i/j)))./(x.*(aw/i).*sqrt(i/j)))
^
and similarly for the other sinh function. Of course this doesn't get you out of the nan problem, it just fixes up the element by element division.
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