I would like to perform one-hot encoding on the vector [1 7 10 9 8 6]' with 10 classes (numbers 1 to 10). The resulting 6x10 matrix should have a 1x10 vector in place of each number, with "1" at the position corresponding to the number and "0" at all other positions.

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MathWorks Support Team
MathWorks Support Team 2024 年 9 月 13 日
編集済み: MathWorks Support Team 2024 年 9 月 13 日

5 投票

This can be done by using a logical operator '==' as follows:
>> vec = [1 7 10 9 8 6]'; % Create the vector>> A = (vec==1:10) % Find the column that corresponds to each vector entry
A = 6×10 logical array 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 1 0 0 0 0
You can learn more about the operator here:

その他の回答 (1 件)

Jon Cherrie
Jon Cherrie 2026 年 2 月 13 日

0 投票

The function onhotencode will do this for you, e.g.,
x = [1 7 10 9 8 6]' ;
classes = 1:10;
y = onehotencode(x,2,"double",ClassNames=classes)
You can use onehotdecode for the reverse operation, which will also work on probability vectors, not just vectors of 1s and 0s

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