- if does not change subsets of an array like that (you would need to use if inside of a loop).
- You also need to read the if documentation to know how it behaves with non-scalar conditions.
- MATLAB does not have ternary logical operators like 0<=x<1. What you wrote is equivalent to (0<=x)<1 which is equivalent to either 0<1 or 1<1 (but the first case will return true when you don't expect it to).
how can i plot the function of each function?
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I want to plot this function
f(x)=sinx, 0<=x<1
0, elsewhere
Then i wrote code for this function
x=-5:0.01:5;
if 0<=x<1
f=sinx;
else
f=0;
end
plot(x,y);
but when i plotted this code then, there was nothing on the graph
what's wrong on this code? and how can i plot this function?
0 件のコメント
採用された回答
Stephen23
2020 年 5 月 16 日
編集済み: Stephen23
2020 年 5 月 16 日
"what's wrong on this code?"
The MATLAB way is to use logical indexing, e.g.:
>> x = -5:0.01:5;
>> y = sin(x);
>> y(x<0|x>=1) = 0;
>> plot(x,y)
3 件のコメント
Stephen23
2020 年 5 月 17 日
Low-level languages: loops and ifs
High-level languages: functions and comprehensions
MATLAB: arrays and indexing
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