Subtracting different sized arrays in intervals

1 回表示 (過去 30 日間)
Kai Hillers
Kai Hillers 2020 年 5 月 8 日
コメント済み: Kai Hillers 2020 年 5 月 8 日
Hello everyone,
i have a problem where i just cant wrap my head around: I have two arrays, one is a 2678400x1 double (call this A) and one is a 4464x1 double (call this B). I want to subtract the first element of B from the first 600 elements of A, then the second element of B from the 601 to 1200 elements of A without using a loop. The calculated array would look something like this:
C(1) = A(1) - B(1)
C(2) = A(2) - B(1)
C(3) = A(3) - B(1)
...
C(601) = A(601) - B(2)
...
C(1201) = A(1201) - B(3)
etc.
I am using MatLab R2015a

採用された回答

Fangjun Jiang
Fangjun Jiang 2020 年 5 月 8 日
A=(1:24)';
B=(1:6)';
C=A-repelem(B,numel(A)/numel(B))
  1 件のコメント
Kai Hillers
Kai Hillers 2020 年 5 月 8 日
Perfect, Fangjun Jiang. You are truly a MVP! :) I didnt know the function repelem() existed and couldn't find it, thanks for helping me out!

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeMatrices and Arrays についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by