# lower triangular semidefinite matrix

4 ビュー (過去 30 日間)
Albert Stirling 2020 年 5 月 4 日
コメント済み: Albert Stirling 2020 年 5 月 4 日
how can i build a sparse matrix in this form for a given semidefinite matrix? i only need the sparse lower triangular of semidefinite matrix
for example a semidefinite matrix as Q0:
2 0 -1
Q0 = 0 0.2 0
-1 0 2
is written as:
i = [1 2 3 3 ];
j = [1 2 3 1 ];
c = [2 0.2 2 -1 ];
where i shows number of row
j shows number of column
and c is the elemnt that belong to (i,j) that is not zero and belong to lower triangular of semidefinite matrix
##### 2 件のコメントなしを表示なしを非表示
Guillaume 2020 年 5 月 4 日
I'm not sure I understand the problem, sparse(i, j, c) would create your sparse matrix.
Guillaume 2020 年 5 月 4 日
Albert Stirling's comment mistakenly posted as an Answer moved here:
I need a simple algorithm that select the non-zero values in shown lower triangular part of this symmetric matrix and return it as below:
i = [1 2 3 3 ];
j = [1 2 3 1 ];
c = [2 0.2 2 -1 ];
i need the algorithm to be flexible so i can give it any desired symmetric matrix and have an answer like the one mentioned.

サインインしてコメントする。

### 採用された回答

Guillaume 2020 年 5 月 4 日
[i, j, c] = find(tril(yourmatrix))
seems to be what you're after.
##### 1 件のコメント-1 件の古いコメントを表示-1 件の古いコメントを非表示
Albert Stirling 2020 年 5 月 4 日
thank you so much that was a quick way to handle this problam.
however i found a long one myself as below:
Q0=[-2 0 0.2;
0 -2 0;
0.2 0 -0.2]
[, c]=size(Q0);
for i=1:c
for j=1:3-i
Q0(i,i+j)=0;
end
end
Q1=sparse(Q0);
[i,j,s] = find(Q1);
f=[i,j,s]'

サインインしてコメントする。

### その他の回答 (1 件)

John D'Errico 2020 年 5 月 4 日

You just want the lower triangle elements. semi-definite-ness is irrelevant to what you asked for at the end.
A = sprand(5,5,.3);
>> full(A)
ans =
0.46421 0.83266 0 0.022104 0.18026
0.26627 0 0 0 0
0 0 0 0 0
0 0 0 0.92865 0
0 0 0.37763 0.42783 0
>> [Rind,Cind,val] = find(tril(A))
Rind =
1
2
5
4
5
Cind =
1
1
3
4
4
val =
0.46421
0.26627
0.37763
0.92865
0.42783
That is how you would EXTRACT the lower triangle into a set of row and column indices, and the non-zero elements in those positions. Which on the face of it, seems to be your question. However, my guess is that you really want to build the sparse matrix from those values? Or, perhaps you just don't understand that sparse matrices already exist in MATLAB and can be used as such? It is not at all clear what is the real problem.
Regardless, if you wanted to build the matrix as a sparse one, then just call sparse using those vectors.
Atril = sparse(Rind,Cind,val,5,5)
Atril =
(1,1) 0.46421
(2,1) 0.26627
(5,3) 0.37763
(4,4) 0.92865
(5,4) 0.42783
>> full(Atril)
ans =
0.46421 0 0 0 0
0.26627 0 0 0 0
0 0 0 0 0
0 0 0 0.92865 0
0 0 0.37763 0.42783 0
##### 1 件のコメント-1 件の古いコメントを表示-1 件の古いコメントを非表示
Albert Stirling 2020 年 5 月 4 日
thank you, your solution seems to be a good way to solve this problam. thank you again.

サインインしてコメントする。

### カテゴリ

Help Center および File ExchangeSparse Matrices についてさらに検索

R2019b

### Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by