How to compare elements with above and below element in a column?

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Masoud Taleb
Masoud Taleb 2020 年 4 月 30 日
コメント済み: Masoud Taleb 2020 年 4 月 30 日
Hello
I have a matrix of 4 columns. I would like to compare each element in 4th column with previous and next element in the same column. If the difference is more than 50, the elemnt should turn to 0. (This is to eliminate unexpectedly high or low values inside 4th column. Other columns should not change at all)
My written code does not work, so I will be glad if some one can help in this. I expect the result look like this:
A = [15 2 7 36
20 3 14 41
25 4 21 0
30 5 28 22]
A = [15 2 7 36
20 3 14 41
25 4 21 567
30 5 28 22]
M = length (A(:,4)),
i = A(1,4) %first element of the column
k = A(M,4) %last element of the column
for T = 2:M-1
idx = A(T,4)
if idx> 'A(T+1,4)'+200
A(idx,4) = 0;
if idx < 'A(T-1,4)'-200
A(idx,4) = 0;
end
end
fname = sprintf('new.csv');
csvwrite (fname,A); % Write to CSV file
end

採用された回答

James Tursa
James Tursa 2020 年 4 月 30 日
Is this what you want?
for T = 2:M
if( abs(A(T,4) - A(T-1,4)) > 50 )
A(T,4) = 0;
end
end
  3 件のコメント
Masoud Taleb
Masoud Taleb 2020 年 4 月 30 日
Oh James.... I found the problem. My values in example matrix were below 50 and in real data file are below 100. Then, many of data turned to 0.
Then, this works.... Thanks.

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その他の回答 (1 件)

Guillaume
Guillaume 2020 年 4 月 30 日
Rather than coming up with your own code, I'd recommend using the filloutliers method. It doesn't have a detection method for 'more than 50 away from the two nearest neighbours' but the many detections methods are probably a lot more robust than this anyway.
A(:, 4) = filloutliers(A(:, 4), 0); %replace outliers by 0
It also has better fill methods than replacing outliers by 0.
  1 件のコメント
Masoud Taleb
Masoud Taleb 2020 年 4 月 30 日
Dear Guillaume
This is so nice way. I did not know there is so short and effective command. I replace above solution with this :) Thanks

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