Simple Iterative expression needed solved

1 回表示 (過去 30 日間)
James Paltani
James Paltani 2020 年 4 月 30 日
コメント済み: Walter Roberson 2020 年 4 月 30 日
Assuming w is an integer (w = 1, 2, 3, …), write an iterative calculation to determine the minimum w value that will bring the result of the following expression to greater than 10,000. Display this minimum w value and the corresponding result of the expression.

回答 (2 件)

Walter Roberson
Walter Roberson 2020 年 4 月 30 日
initialize. while the condition is not met, increment.
  4 件のコメント
James Paltani
James Paltani 2020 年 4 月 30 日
編集済み: James Paltani 2020 年 4 月 30 日
This is what i have so far.. it says illegal "greater than" operator. What should i differently
clc,clear
syms w
e = sqrt((10*w^2)-4*w+2);
for e > 10000,
solve(w)
Walter Roberson
Walter Roberson 2020 年 4 月 30 日
syms w
e = sqrt((10*w^2)-4*w+2);
w = ceil(max(double(solve(e==10000))));
But this does not use a loop like you are required to do. You should not be using symbolic toolbox for this problem.
You should be initializing w to the lowest value of the range. Then you calculate e based on that w. Test whether it has reached the necessary value yet. If it has not, increment w and recalculate e and loop back.

サインインしてコメントする。


Mrutyunjaya Hiremath
Mrutyunjaya Hiremath 2020 年 4 月 30 日
w = 1; y = 0;
while(y < 10000)
% your equation
y = sqrt(10*w*w - 4*w + 2);
w = w + 1;
end
disp(w)
disp(y)
  1 件のコメント
Walter Roberson
Walter Roberson 2020 年 4 月 30 日
We recommend against providing complete solutions to homework assignments.

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeLoops and Conditional Statements についてさらに検索

タグ

製品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by