cfit object in function handle
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I have constructed a curve fit "func" with the following line.
func=fit(x,y,'pchipinterp')
Now I want to use "func" inside an anonymous function as e.g
func2= @ (x,c) x-(c*x+x^2)/func(x)
Then I want to find the root of func2=0 using e.g FZERO as
c=2;
func3=@ (x) func2(x,c)
sol=fzero(func3,<interval>)
Could it be causing any trouble that i am using a cfit object inside the function "func2" ? My solution output is making me suspicious. Note that func2 is not the actual function i'm using but of a similar form.
Any help is much appreciated!
Best regards
1 件のコメント
Adam Danz
2020 年 4 月 29 日
"I am not sure this is a correct way of doing it ..."
Doing what?
"...because the solution is not what at all what you would expect?"
What is the solution and what do you expect?
We obviously cannot run the code nor do we know what the solution is or what you expect the solution to be.
採用された回答
Adam Danz
2020 年 4 月 29 日
My blind guess is that x or c is a vector in which case,
func2= @ (x,c) x-(c.*x+x.^2)./func(x)
% ^ ^ ^
4 件のコメント
Adam Danz
2020 年 4 月 29 日
編集済み: Adam Danz
2020 年 4 月 29 日
Whenever you have a suspicion, simplify the problem and test it with known inputs and outputs.
% Create a cfit object
f = fittype('a*x');
c = cfit(f,2); % This just multiplies x by 2
% Create anon function that uses the cfit obj
fun = @(a,x) c(x) + a; % multiply x by 2 and add a
% Test it with known inputs
fun(10,[2 4 6])
ans =
14 % 2*2 + 10
18 % 4*2 + 10
22 % 6*2 + 10
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