How to find a matrix inside a larger matrix?

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Jose Grimaldo
Jose Grimaldo 2020 年 4 月 28 日
回答済み: SaiDileep Kola 2020 年 5 月 8 日
Im trying to find a smaller matrix inside a larger matrix using explicit loops. I know there is functions and probably easier to locate if there is matching matrix inside a larger matrix. I want to locate matrix M, inside matrix A. How can i set up the for loops since both matrix are different size?
A,6x6 matrix
A=[8 2 9 7 6 7;
9 5 4 1 7 0;
1 9 8 6 7 2;
5 4 1 0 3 0;
9 8 6 8 6 0;
4 1 0 5 4 1];
B, 3x3 matrix
M=[5 4 1; 9 8 6; 4 1 0];
[r,c]=size(A)
[row,col]=size(M)
  2 件のコメント
jessupj
jessupj 2020 年 4 月 28 日
編集済み: jessupj 2020 年 4 月 28 日
if you're beholden to using loops:
you can iterate only a portion of the rows, columnns that fit inside the larger matrix, and test whether the submatrix starting at the appropriate row,col (ie. upper left index) matches the desired matrix. if it matches, store the row,col
match_ul=[]
for rr = 1:(r-row+1)
for cc = 1:(c-col+1);
if isequal( A( rr:(rr+row-1), cc:(cc+col-1) ), M );
match_ul = [match_ul; [rr cc] ];
end
end
end
then you can iterate over the rows of this list to test:
k=1
A( match_ul(k,1)+(0:row-1), match_ul(k,2)+(0:col-1))
ans =
5 4 1
9 8 6
4 1 0
k=2
A( match_ul(k,1)+(0:row-1), match_ul(k,2)+(0:col-1))
ans =
5 4 1
9 8 6
4 1 0
Rik
Rik 2020 年 4 月 28 日
Why do you insist on loops? Or is this a homework assignment?

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回答 (1 件)

SaiDileep Kola
SaiDileep Kola 2020 年 5 月 8 日
Follow the link provided here for a similar query resolved

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