フィルターのクリア

How to use 2D logical mask on an image without for loop?

6 ビュー (過去 30 日間)
xiaojuezi
xiaojuezi 2020 年 4 月 28 日
コメント済み: KSSV 2020 年 4 月 28 日
I have two image matrices A and B with size 512 x 512 x 3, and a logical mask of size 512 x 512. For each position with true value in the mask, I want to set A's value to B's. Currently I only know the for loop solution:
for y = 1 : height
for x = 1 : width
if mask(y,x)
A(y,x,:) = B(y,x,:)
end
end
end
Is there a way to avoid the for loop?

回答 (1 件)

KSSV
KSSV 2020 年 4 月 28 日
B = zeros(512,512,3) ;
for i = 1:3
T1 = B(:,:,1) ;
T2 = A(:,:,i) ;
T1(idx) = T2(idx) ;
B(:,:,i) = T1 ;
end
  2 件のコメント
xiaojuezi
xiaojuezi 2020 年 4 月 28 日
Does this solution set B's value as A's instead of other way round as in the for loop?
KSSV
KSSV 2020 年 4 月 28 日
It sets A's values to B. You can change it, if you want the other way.

サインインしてコメントする。

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by