Magnitude and direction from north and east components
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I have displacement data components along north and east how to find its magnitude and direction with reference to north(0-360) in matlab. The components may have same sign or opposite both possible.
Deepak Gupta 2020 年 4 月 22 日
編集済み: Deepak Gupta 2020 年 4 月 22 日
You can think of North and East as your X and Y. As you have taken north as reference so use below formulas to calculate magnitude and angle.
Magnitude = sqrt(North^2+East^2);
Theta = atan((-East)/North);
I am using -East because East is 90 degree closewise to North and atan calculates angles in counter clockwise directions from reference.
その他の回答 (1 件)
KSSV 2020 年 4 月 22 日
If (x,y) is a componenet
m = sqrt(x^2+y^2) ; % magnitude
theta = atan(y/x) ; % direction
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