fit a curve through selected points with own function
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Hey!
I have a problem.. I don't know why I'm having such a hard time figuring it out.
I have data say
x = [1 2 3 4 5 6 7 8]
y = [3 4 5 6 7 8 9 10]
What I need is to plot it, then choose four points (say x=2, y= 4 and x= 4, y= 6 etc)
and make a fit through only these 4 points. The fit should be of the form x**-n, where n is a real number.
I can then play around with n, to find the best fit, once I can get x,y and this fit with 4 selected points on a same graph.
All help is appreciated, thank you!
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回答 (2 件)
Michael Soskind
2020 年 4 月 20 日
Hi Steve,
With regards to curve fitting, when you choose the points, then you can fit it to any function using lsqcurvefit, since you know x and y.
Here is an example similar to the one you describe above. I select the values you described, and show the result in a plot:
x = [1 2 3 4 5 6 7 8];
y = [3 4 5 6 7 8 9 10];
range = [2,3,4,7];
xdata = x(range);
ydata = y(range);
fun = @(c, xdata) c(1)*xdata + c(2);
x0 = [1.2,1.8]
coeffs = lsqcurvefit(fun, x0, xdata, ydata);
figure(); hold on;
plot(xdata, ydata, 'o');
plot(xdata, fun(coeffs, xdata))
I hope that helps, and is similar to what you are looking for,
Michael
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Michael Soskind
2020 年 4 月 20 日
I forgot to mention, the function definition is important, c is an array of the coefficients, and since I use a linear function, I have a slope term and offset term. In your case, you can scale the polynomial and have the power terms selected by the curve fitting routine.
fun = @(c, xdata) c(1)*xdata.^c(2);
Ameer Hamza
2020 年 4 月 20 日
You can use the curve fitting toolbox to find the fit of the form you described in the question
x = [1 2 3 4 5 6 7 8];
y = [3 4 5 6 7 8 9 10];
ft = fittype('x^-n');
fit_model = fit(x([2 4]).',y([2 4]).',ft);
plot(x, y, '+', x, fit_model(x))
you can check the value of n from 'fit_model'
>> fit_model
fit_model =
General model:
fit_model(x) = x^-n
Coefficients (with 95% confidence bounds):
n = -1.327 (-3.497, 0.8423)
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