FFT frequency shift during downsampling

2 ビュー (過去 30 日間)
A VP
A VP 2020 年 4 月 17 日
コメント済み: A VP 2020 年 4 月 19 日
I have a signal at 1000Hz and I am calculating FFT of the signal. I see it's first order contents at 11Hz. However when I downsample the signal to 100Hz and re-run FFT, I do not see a peak at 11Hz. Instead I see a peak at 9.6Hz.
Can anyone explain why I see this behavior when I downsample a signal?
  6 件のコメント
David Goodmanson
David Goodmanson 2020 年 4 月 18 日
Hey Kalyan,
In the link they appear to be transforming a function cos(30*x) to the spacial frequency domain. In the time domain this would be cos(30*t) = cos(w*t) so w = 30. That means f = w/(2*pi) which is around 5, which is where their peak is. I don't see what the problem is.
A VP
A VP 2020 年 4 月 19 日
Hi David Goodmanson,
Yes, I am doing an FFT of a 600s signal sampled at 100Hz. [total : 600001 samples]. I am looking at FFT of every 5seconds [500 samples] and have used a Hanning window with a 50% overlap.

サインインしてコメントする。

回答 (0 件)

カテゴリ

Help Center および File ExchangeMultirate Signal Processing についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by