solving and finding c1 c2 values

Eq4 =

(2682754076831727*c1)/8388608 + (2682754076831727*c2)/8388608 + (2682754076831727*c3)/8388608 + (3167144087592971*(c1 + c2 + c3)^3)/55083008 - 24

Eq5 =

(2682754076831727*c1)/8388608 + (2682754076831727*c2)/8388608 + (2682754076831727*c3)/8388608 + (3167144087592971*(c1 + c2 + c3)^3)/55083008 - 24

>>

Answer 1

[Star Strider]

Try this:

syms c1 c2 c3 
Eq4 = (2682754076831727*c1)/8388608 + (2682754076831727*c2)/8388608 + (2682754076831727*c3)/8388608 + (3167144087592971*(c1 + c2 + c3)^3)/55083008 - 24;
Eq5 = (2682754076831727*c1)/8388608 + (2682754076831727*c2)/8388608 + (2682754076831727*c3)/8388608 + (3167144087592971*(c1 + c2 + c3)^3)/55083008 - 24;

S = solve(Eq4,Eq5);
c1 = S.c1
c2 = S.c2

Note that ‘c1’ is a function of ‘c3’, so unlless ‘c3’ has a numeric value or an expression of its own that would provide a numeric value for it, a strictly numeric solution is not possible.