PI BLOCK IN SIMULINK

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Uzair Akhtar
Uzair Akhtar 2020 年 4 月 15 日
回答済み: Animesh 2024 年 8 月 22 日
I have a model in simulink with a PI controller and a transfer function which is shown below.
The PI controller is 3.15(1+2.6s/2.6s) which I have put in ideal form where the proportional(P) is 3.15 and the integral(I) is 2.6 however Im not getting the correct trace on the scope
However when I replace the PI controller with this input output block I have shown below I get the correct answer. Can someone explain what I am doing wrong with the PI block, thanks.
This is what's inside the subsystem input output block.

回答 (1 件)

Animesh
Animesh 2024 年 8 月 22 日
If you look at “PI controller” block’s dialog box, you can see that compensator formula is:
Given the value of “P = 3.15” and “I = 2.6” would generate the compensator as:
But the desired compensator is:
To obtain the above result use, “P = 3.15” and “I = 3.15/2.6”.
Here is an image with correct configurations:
You can refer to the following MathWorks documentation for more information on "PI Controller" block:

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