How created a graph from unordered node list?

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Mohammad Shapouri
Mohammad Shapouri 2020 年 4 月 6 日
コメント済み: Mohammad Shapouri 2020 年 4 月 6 日
I want to created a graph from an unordered list of nodes. However, Matlab creat graph from ordered node numbers. For example, My node list is as :
source=[1,4,8,7];
Target=[7,8,1,4];
Now this would be the result if I plot the graph from this source and target nodes:
G=graph(source,Target);
P=plot(G);
The results shows the range of nodes from 1 to 8; however, These nodes don't exist in this network. This is problematic since I have a huge road network like this (34000 unordered pairs of source and targets) and each node has and coordiantion. This seroiusly cause problem while I'm trying to plot it with coordiantes. I tried to remove those nodes but it completly changes the graph (I have no Idea why this happening). Thank you in advance for any advice or help.

採用された回答

Christine Tobler
Christine Tobler 2020 年 4 月 6 日
When a graph or digraph is specified using numbers, the assumption is that all nodes of this graph have numbers from 1:numberOfNodes. This is not the case when a graph or digraph is constructed from strings, so the simplest workaround is
G = graph(string(source), string(Target));
  2 件のコメント
Mohammad Shapouri
Mohammad Shapouri 2020 年 4 月 6 日
編集済み: Mohammad Shapouri 2020 年 4 月 6 日
I did try this way but it's problematic when I'm trying to plot it based on node coordinates because the node order is not the same as numbers when you change numbers to string. I'm trying to change the coordiantion order based on string order. I hope it works. However, I believe this assumption should change because when you create a graph based on edge list, actually you specify the node numbers.
Mohammad Shapouri
Mohammad Shapouri 2020 年 4 月 6 日
It worked after I change the arrangement of coordiantes based on string format. Thank you.

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その他の回答 (1 件)

darova
darova 2020 年 4 月 6 日
Try this
x = x(:);
y = y(:);
plot([x(source) x(target)],[y(source) y(tagrget)])
or patch function
fv.vertices = [x(:) y(:)];
fv.faces = [source(:) target(:)]];
patch(fv)
  5 件のコメント
darova
darova 2020 年 4 月 6 日
Can you attach small part of the data or simplified example?
Mohammad Shapouri
Mohammad Shapouri 2020 年 4 月 6 日
The problem solved by using string format. Thank you.

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