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repeat the iteration with an error using try/catch

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Mos_bad
Mos_bad 2020 年 4 月 3 日
編集済み: James Tursa 2020 年 4 月 4 日
I wrote a nested for loop to exexcute a huge number of iterations. However, sometimes an error stops the program. I want to repeat the iEv'th iteration in case an error occurs and then continue to next iteration. Please see below the code and let me know if it should be modified.
for iTcm=1:nTcm
for iScen=1:nScen
for iEv=1:nEv
try
MyProgramHere
catch ME
disp(ME);
fprintf('Retrying the program...\n');
end
end
end
end

採用された回答

James Tursa
James Tursa 2020 年 4 月 3 日
編集済み: James Tursa 2020 年 4 月 3 日
Maybe this construct does what you want
while( true )
try
MyProgramHere
break
catch ME
disp(ME);
fprintf('Retrying the program...\n');
end
end
  3 件のコメント
Mos_bad
Mos_bad 2020 年 4 月 3 日
This code didn't work either. Any help?
James Tursa
James Tursa 2020 年 4 月 3 日
編集済み: James Tursa 2020 年 4 月 4 日
No. I meant exactly what I wrote, without this line:
iEv = iEv - 1; % delete this line
By getting rid of this line, it will keep repeating the same iteration indefinitely until it passes. iEv doesn't change until you do the iteration successfully. If you want a limit on the number of tries before you generate an error then additional code would need to be added.

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その他の回答 (1 件)

darova
darova 2020 年 4 月 3 日
編集済み: darova 2020 年 4 月 3 日
My proposition
for iTcm=1:nTcm
for iScen=1:nScen
iEv = 0;
while iEv <= nEv
iEv = iEv + 1;
try
MyProgramHere
catch ME
iEv = iEv-1;
disp(ME);
fprintf('Retrying the program...\n');
end
end
end
end
  4 件のコメント
darova
darova 2020 年 4 月 3 日
What about this. I improved my code
Mos_bad
Mos_bad 2020 年 4 月 3 日
With the improved code, when the iEv count reaches to nEv, the program control goes immediately to the catch block. So the program stops without going to (iScen+1)th iteration.

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