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Processing 2D into 3D matrix

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Minas Emiris
Minas Emiris 2020 年 4 月 1 日
コメント済み: Minas Emiris 2020 年 4 月 1 日
Hi all.
I have a matrix (phi), say of 1502 rows (harmonic) by 10 columns (observations), where the i,j th element represents the phase of the ith harmonic of the jth observation; say the name of the matrix is X;
I need to find the modeshape corresponding to each harmonic; say y = sin(x + phi(i,j)), where x is a position vector, say x = 0:1:11 (11 position elements);
But since each of these modeshapes has its own corresponding 11 'y' values, what I need is a 3D matrix with size 1502x10x11 with all the modeshape values. How can I use the 2D matrix phi to get the 3D matrix (Modeshapes) that I want?
I tried the following code, which gives a better indication of what I need but it didn't work.
modeshapes = zeros(1502,10,11)
x = 0:1:11
for i = 1:1502
for j = 1:10
modeshapes(i,j,:) = sin(phi(i,j)+x)
end
end

採用された回答

Andrei Bobrov
Andrei Bobrov 2020 年 4 月 1 日
modeshapes = sin(phi + reshape(x,1,1,[]));
  1 件のコメント
Minas Emiris
Minas Emiris 2020 年 4 月 1 日
Thank you very much, this works.

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その他の回答 (1 件)

J Chen
J Chen 2020 年 4 月 1 日
You need to change the following statement
x = 0:1:11
x has 12 elements but the modeshapes array only allows 11 elements in the third dimension.
  2 件のコメント
Minas Emiris
Minas Emiris 2020 年 4 月 1 日
Pardon, it's x = 0:1:10; but it's not because of what you're saying.

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