Filtering Columns by Contents of Rows

I have arrays that look like this:

A =

     1   NaN   NaN
     2     3     4
     2     5   NaN

I want to remove columns that contain rows with less than n non-NaN entries. In this case, with n=2, the first column of A would be removed, since the first row contains only 1 non-NaN value. The resulting array would be:

A = 
    
    NaN   NaN
      3     4
      5   NaN

Is there a compact way to do this? I hope this explanation makes sense!

Answer 1

[Birdman]

n=2;
A(:,(sum(~isnan(A),2)<n).')=[]

[Justin Delano]

Hello, thank you I think this is closer, but this gives me errors when I don't use a square array. Here is an example, where column 3 should be removed due to row 4:

>> A = [1, 2, NaN; 10, NaN, 5; 1, 3, 5; NaN, NaN, 6]

A =

     1     2   NaN
    10   NaN     5
     1     3     5
   NaN   NaN     6

>> A(:,(sum(~isnan(A),2)<2).')
The logical indices in position 2 contain a true value outside of the array bounds.
 
>> (sum(~isnan(A),2)<2).'

ans =

  1×4 logical array

   0   0   0   1

[Birdman]

Try the following line for both cases:

n=2;
A(:,any(~isnan(A) & A<n,1))=[]

[Justin Delano]

For this new case, it removed the first column, as opposed to the third column, unfortunately.