Filtering Columns by Contents of Rows

3 ビュー (過去 30 日間)
Justin Delano
Justin Delano 2020 年 3 月 30 日
コメント済み: Justin Delano 2020 年 3 月 30 日
I have arrays that look like this:
A =
1 NaN NaN
2 3 4
2 5 NaN
I want to remove columns that contain rows with less than n non-NaN entries. In this case, with n=2, the first column of A would be removed, since the first row contains only 1 non-NaN value. The resulting array would be:
A =
NaN NaN
3 4
5 NaN
Is there a compact way to do this? I hope this explanation makes sense!

回答 (1 件)

Birdman
Birdman 2020 年 3 月 30 日
n=2;
A(:,(sum(~isnan(A),2)<n).')=[]
  3 件のコメント
Birdman
Birdman 2020 年 3 月 30 日
Try the following line for both cases:
n=2;
A(:,any(~isnan(A) & A<n,1))=[]
Justin Delano
Justin Delano 2020 年 3 月 30 日
For this new case, it removed the first column, as opposed to the third column, unfortunately.

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeMatched Filter and Ambiguity Function についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by