How to stock a vector in a vector

6 ビュー (過去 30 日間)
Maxime Chapellier
Maxime Chapellier 2020 年 3 月 27 日
コメント済み: Maxime Chapellier 2020 年 3 月 27 日
Hello everybody !
I'm in trouble with this : I would like to change the value of water_u in my loop and to stock the result in X (a 3 colomns or 3 rows matrice).
It doesn't work... Can someone help me ? :)
Many thanks in advance
clear all
close all
clc
water_density = [0.997]; %[g/cm3]
water_att = [1.64e-1; 6.40e-2; 2.92e-2]; %[cm2/g] @100, 1000, 10000 keV
water_u = water_density.*water_att; %[cm-1]
R = rand(1,1000);
for i=1:3
X = -(log10(1-R)./water_u(i));
end
  2 件のコメント
Geoff Hayes
Geoff Hayes 2020 年 3 月 27 日
Maxime - your R is a 1x1000 matrix. Is that correct? It seems that you are using a different value of water_u in your loop (good), but because of the size of R, the X can never be a 3x1 or 1x3 matrix.
Maxime Chapellier
Maxime Chapellier 2020 年 3 月 27 日
編集済み: Maxime Chapellier 2020 年 3 月 27 日
Thanks for your answer. Yes it is correct, in fact I would like my X a 3x1000 matrix or a 1000x3 matrix. I try to configure my X before with a zeros(3,1000) but it doesn't solve the problem

サインインしてコメントする。

採用された回答

Geoff Hayes
Geoff Hayes 2020 年 3 月 27 日
編集済み: Geoff Hayes 2020 年 3 月 27 日
Maxime - try doing
X = zeros(3,1000);
for i=1:3
X(i,:) = -(log10(1-R)./water_u(i));
end
where we use the : to indicate all columns in the ith row of X X(i,:) via
X(i,:) = ...
  1 件のコメント
Maxime Chapellier
Maxime Chapellier 2020 年 3 月 27 日
It works !!!
Thank you so much :D

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeCreating and Concatenating Matrices についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by