フィルターのクリア

problem to write a condition for 'if'

1 回表示 (過去 30 日間)
NA
NA 2020 年 3 月 26 日
回答済み: Birdman 2020 年 3 月 26 日
I want to save A_new according to this condition:
If A_new decreases the length of B, I want to save it.
I wrote a code like this but I have a problem to write a condition
A = {[1,2,3,4], [1,2,3,6], [1,2,3,8], [1,2,6,7,8], [1,6,8], [2,3,4,7], [3,4,6], [3,4,6,7], [3,4,6,7,8], [3,6,8], [6,7,8], [1,5]};
B =[1 2; 1 4; 1 8; 1 5; 1 6; 2 7; 2 3; 3 6; 3 8; 3 4; 4 7; 4 6; 7 6; 7 8; 6 8];
B_bk = B;
A_new = cell([],1);
length_B = cell([],1);
%% sort A
[~,I] = sort(cellfun(@length,A));
A = A(I);
C = [];
if isempty(B)==0
for i=1:length(A)
temp = [A{i} A{i}(1)];
C = [C;[temp(1:end-1)' temp(2:end)']];
[~,X] = setdiff(sort(B_bk,2),sort(C,2),'rows','stable');
B = B_bk(X,:);
length_B{i} = length(B);
%% problem to write condition
if length_B{i}- length_B{i-1}>0 %%???
A_new{i} = A{i};
end
end
end
result should be
A_new = {[1,5],[1,6,8],[3,4,6],[3,6,8],[6,7,8],[1,2,3,4],[2,3,4,7]};
I think it would be better way to write this code.

採用された回答

Birdman
Birdman 2020 年 3 月 26 日
Try the following code:
A = {[1,2,3,4], [1,2,3,6], [1,2,3,8], [1,2,6,7,8], [1,6,8], [2,3,4,7], [3,4,6], [3,4,6,7], [3,4,6,7,8], [3,6,8], [6,7,8], [1,5]};
B =[1 2; 1 4; 1 8; 1 5; 1 6; 2 7; 2 3; 3 6; 3 8; 3 4; 4 7; 4 6; 7 6; 7 8; 6 8];
B_bk = B;
A_new = cell([],1);
length_B = cell([],1);
%% sort A
[~,I] = sort(cellfun(@length,A));
A = A(I);
C = [];
for i=1:length(A)
temp = [A{i} A{i}(1)];
C = [C;[temp(1:end-1)' temp(2:end)']];
[~,X] = setdiff(sort(B_bk,2),sort(C,2),'rows','stable');
B = B_bk(X,:);
length_B{i} = length(B);
if i==1
A_new{i} = A{i};
end
%% problem to write condition
if i>1
if length_B{i-1}- length_B{i}>0 %%???
A_new{i} = A{i};
end
end
end
A_new=A_new(~cellfun(@isempty,A_new))

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeSource Coding についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by