Geometry function - domain sketch
3 ビュー (過去 30 日間)
古いコメントを表示
Hi, I am trying to sketch the domain for PDE solver. It is similar to the example function CIRCLEFUNCTION.m.
My domain has four edges. Left and right edges are parallel to the y-axis. Top and bottom edges are curves:
I have following so far:
________________________
function [x,y]= dom(bs,s)
if nargin = = 0
x=4;
end
if nargin = = 1
A=[ 0, 1, 1, 0 ;
1, 1, 0 , 0 ;
1, 1, 1, 1 ;
0, 0, 0, 0]
I don't know where to go from there. I read examples online, but they are complicated.
You could choose curves connecting top vertices and bottom vertices to be simple quadratic curves, vertices are (0,0), (1,0), (1,1), (0,1).
Thank you!
Sandy
2 件のコメント
採用された回答
darova
2020 年 3 月 21 日
Try pdepoly
x = 0:0.1:1;
y = x.^2-x+1;
x = [0 x 1];
y = [0 y 0];
pdepoly(x,y)
9 件のコメント
darova
2020 年 3 月 22 日
What about this?
x= 0:0.1:1;
y= x.^2-x+1;
x=[0 x 1];
y=[0 y 0];
pdepoly(x,y);
pdetool('initmesh')
% pdetool('refine')
darova
2020 年 3 月 22 日
Maybe it would be helpful
x= 0:0.1:1;
y= x.^2-x+1;
x=[0 x 1];
y=[0 y 0];
gd = [2;length(x);x(:);y(:)]; % geometry description matrix
dl = decsg(gd); % decompose matrix
[p,e,t] = initmesh(dl); % create mesh
subplot(121)
pdemesh(p,e,t)
axis equal
subplot(122)
[p1,e1,t1] = refinemesh(dl,p,e,t);
pdemesh(p1,e1,t1)
axis equal
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Geometry and Mesh についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!