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System of Second order order differential Equations referencing the 0th derivative

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The following code refers to the system of differential equations in which only the first and second derivatives are included. How can the
zeroth derivative be referred to, for example, what if one of the equations was x'' = x*sqrt(x'^2+y'^2) rather than x'' = sqrt(x'^2+y'^2) - how could x be referred to? Writing
xy(0) for the 0th derivative or the position vector returns an error message but I am not sure how to modify the code. For example,
changing the first line to xy = zeros(6,1) does not help.
function xy=PackageMotion(t,x)
% the differential equation soltuion
xy=zeros(4,1);
% The paramter of the package
m=1; g=9.82; Cd=0.035;
% The differential equation described in state space form
%xy(1)
xy(1)=x(2); %first derivative (velocity)
xy(2)=(-Cd*x(2)*sqrt(x(2)^2+x(4)^2))/m;
xy(3)=x(4);
xy(4)=(-Cd*x(3)*sqrt(x(2)^2+x(4)^2))/m-g;
end
[SL: formatted the text of the question as text rather than code]
  1 件のコメント
Walter Roberson
Walter Roberson 2020 年 3 月 17 日
If you have the symbolic toolbox, then I suggest following the steps in the first example in odeFunction

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Ameer Hamza
Ameer Hamza 2020 年 3 月 17 日
For the state space system inside the PackageMotion function, the variables are in this order
x(1) -> x-position
x(2) -> x-veclcity
x(3) -> y-position
x(4) -> y-velocity
So your 2nd equation should be
xy(2)=(-Cd*x(1)*sqrt(x(2)^2+x(4)^2))/m;

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