combining 3 for loops
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Hi, All!
I have 3 "for" loops but i confuse when combining one and another. I need vector u, depend on x(j)-x(i) and x(i,t)-x(i,t-1)
this is the best function i've tried before. So glad to know that anyone can correct and help me :)
for t=1:1000
for i=1:5
for j=1:5
u(i,j)= a1*adj2(i,j)*(x(j)- x(i))+a2*(x(i,t)-x(i,t-1));
end
end
u=sum(u,2)
end
3 件のコメント
Bob Thompson
2020 年 3 月 16 日
Also, what exactly is the problem you're experiencing? Are you getting an error message, or are you just not getting the output you would expect. If the output is different, what does it look like, and how were you expecting it to be different?
To add to tmarske's point about the different forms of indexing, if x is a 2D array then x(j) - x(i) will return a reduced vector, while x(i,t) - x(i,t-1) will return a single element. This is not inherently a problem, depending on the size of a1, adj2, and a2, but MATLAB will not let you perform a '+' operation on two components of different sizes like that.
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Sriram Tadavarty
2020 年 3 月 17 日
編集済み: Sriram Tadavarty
2020 年 3 月 17 日
Hi Nur,
If the code is updated to run from time t set from 2 to 1000, this should go away with the error you see.
The subtraction of x(j) and x(i) would only do it for the first five elements all the time. I think this is not the intention. It should be x(j,t) and x(i,t)
With these changes the code looks as such:
for t=2:1000
for i=1:5
for j=1:5
u(i,j,t)= a1*adj2(i,j)*(x(j,t)- x(i,t))+a2*(x(i,t)-x(i,t-1));
end
end
u=sum(u,2)
end
u = permute(u,[1 3 2]);
Hope this helps.
Regards,
Sriram
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