Legend position according to axes
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Hello I want to reposition the legend from the start of axes (not in the middle) like this
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/276286/image.png)
Can we do this? Here is my code
x = 1:10; y1 = 4*x; y2 = 3*x + 5; figure(1), plot(x,y1,'b',x,y2,'r')
legend('Line 1','Line 2','Location','NorthOutside','Orientation','horizontal','Box','off')
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回答 (1 件)
Jakob B. Nielsen
2020 年 3 月 10 日
You can specify the position of your legend yourself with coordinates, rather than using a predetermined location. First two coordinates are the x and y start, second coordinates are the x-wise length and y-wise height of the legend. For example:
x = 1:10; y1 = 4*x; y2 = 3*x + 5; figure(1), plot(x,y1,'b',x,y2,'r')
legend('Line 1','Line 2','Position',[0.2 0.92 0.15 0.0869]);
legend('Orientation','horizontal')
legend('boxoff')
4 件のコメント
Jakob B. Nielsen
2020 年 3 月 10 日
編集済み: Jakob B. Nielsen
2020 年 3 月 10 日
Weird! It seems the properties changes simply from the maximising of the window. I dont know why that is the case...
if you put in
x = 1:10; y1 = 4*x; y2 = 3*x + 5;
ax=axes;
plot(ax,x,y1,'b',x,y2,'r')
lg=legend('Line 1','Line 2','Position',[0.2 0.92 0.15 0.0869],'Orientation','horizontal','Box','off');
and then inspect lg, it has Position: [0.1250 0.9396 0.3000 0.0476] (which is not even the position we specify)... But then when maximising the window and doing nothing else, lg now has Position: [0.2313 0.9542 0.0875 0.0185].
I dont know... If you need the plot maximised, then plot it maximised to begin with and set the legend position accordingly, I guess?
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