i want to generate a sequence of n numbers

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Matte Rennerts
Matte Rennerts 2020 年 3 月 9 日
回答済み: Voss 2023 年 10 月 19 日
How would i generate a secuence of N amount of numbers starting at -4 and going up in steps of 2?
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  3 件のコメント
Matte Rennerts
Matte Rennerts 2020 年 3 月 9 日
Those sequence codes work if i have an end value of the secuence but i need the sequence to contain n amount of elements regardless of the last value
Robert U
Robert U 2020 年 3 月 9 日
Those sequences work with variables as end values as demonstrated in the answer by Benni.

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採用された回答

Benjamin Großmann
Benjamin Großmann 2020 年 3 月 9 日
編集済み: Benjamin Großmann 2020 年 3 月 9 日
You can create sequences with the colon operator (:), for exapmle
v = [4:2:100];
creates v = [4, 6, 8, ... , 100] with values starting at 4, an increment of 2 and stop value 100.
For N numbers starting at -4 and an increment of 2, you have to calculate the stop value:
N = 10;
start_val = -4;
inc = 2;
stop_val = (N-1)*inc + start_val;
v = [start_val:inc:stop_val];

その他の回答 (1 件)

Voss
Voss 2023 年 10 月 19 日
start = -4;
increment = 2;
N = 8;
sequence = start + (0:N-1)*increment;

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