Reshape the vector as indexed matrix.
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I need to reshape each row vector in 'x' to the 2D matrix as indexed in 'idx'. I have written the code and working fine. But it takes more time as the number of rows in x is high. Is there any way to reduce the execution time?
x=ones(4732,28000);
idx = buffer(1:28000,10,5,'nodelay');
tic
for i=1:4732
x1=x(i,:);
y=x1(idx);
end
toc
Elapsed time is 1.450427 seconds.
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回答 (1 件)
Alex Mcaulley
2020 年 3 月 6 日
Yes, just removing the for loop because this loop doesn't do anything in your code.
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