How do I loop trough variables
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How do I loop throug variables like this?
a=1;
b=2;
c=3;
for Q=[a b c]
Y=Q
end
The result i would like is:
y = 1
y = 2
y = 3
5 件のコメント
Guillaume
2020 年 3 月 6 日
編集済み: Guillaume
2020 年 3 月 6 日
Are the variables actually tables which would show in the variable browser as a 9x14 table, or cell arrays which would show in the variable browser as 9x14 cell?
Also, what do you want to do with your loop?
回答 (1 件)
Stephen23
2020 年 3 月 6 日
編集済み: Stephen23
2020 年 3 月 6 日
"Why is that?"
Your confusion stems from several things.
- [] square brackets are a concatenation operator, not a "list" operator (which MATLAB does not have). So you took three 9x14 cell arrays and concatenated them horizontally to get one 9x42 cell array (not a "list" of separate arrays as you seemed to be expecting). If you want to store several arrays in a container, then use a cell array.
- Without realizing it, you are looping over the columns of that 9x42 cell array. The for documentation explains that if the values to be iterated over are a non-vector array, then for will iterate over its columns. I have never seen anyone rely on this "feature".
I would avoid your approach of iterating over data or over arrays: it is much more robust to iterate over indices:
C = {arr1,arr2,arr3}; % cell array
for k = 1:numel(C)
Y = C{k};
... do whatever with Y
end
2 件のコメント
Guillaume
2020 年 3 月 6 日
"I have never seen anyone rely on this "feature"."
I use it sometimes, but it is indeed very rare that you just want to iterate over columns without knowing their indices.
Guillaume
2020 年 3 月 6 日
"would avoid your approach of iterating over data or over arrays"
Totally agree.
Even better would be to avoid creating these numbered arrays in the first place. There should only be one variable to start with, either a cell array or in this case since all the arrays are the same size, a 3D matrix.
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