How can I find the position of a real number in a vector?

4 ビュー (過去 30 日間)
Cantor Set
Cantor Set 2020 年 3 月 5 日
編集済み: James Tursa 2020 年 3 月 5 日
I have a vector v:
v=[-0.9990;0.8988;2;3];
I want to find the position of -0.9990.
I used find(x==-0.9990) it does not work.
Any solutions?
Thanks

採用された回答

James Tursa
James Tursa 2020 年 3 月 5 日
編集済み: James Tursa 2020 年 3 月 5 日
Welcome to the world of floating point arithmetic. The number you are searching for cannot be represented exactly in IEEE double precision, so calculations involving it are subject to roundoff errors.
You will need to do the search with some tolerance. E.g.,
find( abs(x - (-0.9990)) < 1e-10 )
P.S. Your example actually does work if you use "v" instead of "x". I am assuming your actual v is built differently. Or maybe the typo is the entire problem.

その他の回答 (1 件)

Cameron B
Cameron B 2020 年 3 月 5 日
find(v==-0.999)

カテゴリ

Help Center および File ExchangeMatrix Indexing についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by