I've got a problem with optimization and using a variable for exponent

Here is my matlab codeR

x = optimvar('x','type','integer','LowerBound',0,'UpperBound',48);

y = optimvar('y','type','integer','LowerBound',0,'UpperBound',48);

obj = fcn2optimexpr(@objfunx,x,y);

prob = optimproblem('Objective',obj);

con1 = x <= 48; prob.Constraints.constr = con1;

con2 = y <= 48; prob.Constraints.constr = con2;

con3 = (1-((0.2.^x))) + ((0.2.^x)).*(1-((0.3.^y))) >= 0.99;

prob.Constraints.constr = con3;

x0.x = 0; x0.y = 0;

show(prob)

function f = objfunx(x,y)

f =(60).*(x) + ((0.2.^x)).*(y).*(20);

end

and I got this error message

Error using optim.internal.problemdef.Power

Exponent must be a finite real numeric scalar.

Error in .^

Error in Test (line 8)

I want to get solution x, y

how can I solve this problem? I'm going to appreciate if you give me whole code

Answer 1

[Alan Weiss]

Optimization Toolbox™ does not support general nonlinear integer programming. Use ga or surrogateopt for nonlinear integer programming.

Or, for this problem, you could do exhaustive search; there are fewer than 2500 = 50^2 possibilities.

Alan Weiss

MATLAB mathematical toolbox documentation

[Minsu Seo]

Thanks Alan Weiss, I already solved this problem with exhaustive search you mentioned.

I just wondered if I could solve that problem using some internal function that the MATLAB provides.

Your answer is really helpful for me and thank you again.