Filtering through multiple vectors for a single set of values

3 ビュー (過去 30 日間)
Chad Williams
Chad Williams 2020 年 2 月 26 日
コメント済み: Chad Williams 2020 年 2 月 26 日
I get the roots below using an equation solver & filtering out "unrealistic" roots with conditional/logical statements.
The part I'm stuck on is on how to code this proccess:
1) Identify the common integer at the beginning of the vector sets between Q1 - Q6 (in this case, 3)
2) Filter out the other vector sets (2,4)
3) Pull out the long decimal number from the #3 vector sets & assign that as the new Q1 Q2 etc
Q1 =
[ 2, 1, 1, 0.058437210716851634542028894189494]
[ 3, 1, 1, 0.058688566689220710419984397081727]
Q2 =
[ 2, 1, 1, 0.0098069127074167821263054682858129]
[ 3, 1, 1, 0.0078508603596354954926620927235173]
Q3 =
[ 2, 1, 1, 0.0015627892831483654579711058105059]
[ 3, 1, 1, 0.0013114333107792895800156029182727]
Q4 =
[ 2, 1, 1, 0.041562789283148365457971105810506]
[ 3, 1, 1, 0.041311433310779289580015602918273]
Q5 =
[ 3, 1, 1, 0.00083770632958521492732230435821]
[ 4, 1, 1, 0.020473081482478049769416844651268]
Q6 =
[ 3, 1, 1, 0.01083770632958521492732230435821]
[ 4, 1, 1, 0.030473081482478049769416844651268]
  2 件のコメント
Jacob Wood
Jacob Wood 2020 年 2 月 26 日
Will there always be a single integer that appears once in every Q_i?
Chad Williams
Chad Williams 2020 年 2 月 26 日
Yes it's purposely put there so the vector can be identified & only exists to point to the root. It will always be 1,2,3 & 4 for this application.
Below is the orginal output where you can see what would be 1 & 4 being filtered out as they are negative.
I just get stuck on trying to translate into code.
Q1 =
-0.15604402697446315680842658977416
0.058437210716851634542028894189494
0.058688566689220710419984397081727
-0.05986135947318542852737264354485
Q1 =
[ 2, 0.058437210716851634542028894189494]
[ 3, 0.058688566689220710419984397081727]

サインインしてコメントする。

回答 (2 件)

KSSV
KSSV 2020 年 2 月 26 日
1) Identify the common integer at the beginning of the vector sets between Q1 - Q6 (in this case, 3)
Read about unique for this.
2) Filter out the other vector sets (2,4)
Use ismember for this.
3) Pull out the long decimal number from the #3 vector sets & assign that as the new Q1 Q2 etc
You can use logical indexing for this.

Jacob Wood
Jacob Wood 2020 年 2 月 26 日
編集済み: Jacob Wood 2020 年 2 月 26 日
Chad,
This might be a solution for you. It picks the most common root label and grabs all of them:
Q1 = [ 2, 1, 1, 0.058437210716851634542028894189494;
3, 1, 1, 0.058688566689220710419984397081727];
Q2 = [ 2, 1, 1, 0.0098069127074167821263054682858129;
3, 1, 1, 0.0078508603596354954926620927235173];
Q3 = [ 2, 1, 1, 0.0015627892831483654579711058105059;
3, 1, 1, 0.0013114333107792895800156029182727];
Q4 = [ 2, 1, 1, 0.041562789283148365457971105810506;
3, 1, 1, 0.041311433310779289580015602918273];
Q5 = [ 3, 1, 1, 0.00083770632958521492732230435821;
4, 1, 1, 0.020473081482478049769416844651268];
Q6 = [ 3, 1, 1, 0.01083770632958521492732230435821;
4, 1, 1, 0.030473081482478049769416844651268];
Q = [Q1;Q2;Q3;Q4;Q5;Q6];
select_int = mode(Q(:,1));
roots = Q(Q(:,1)==select_int,4);
  3 件のコメント
Jacob Wood
Jacob Wood 2020 年 2 月 26 日
I'm not sure I'm following. What is happening in these lines? Is this output from running the code?
[ 2, 0.058437210716851634542028894189494]
[ 3, 0.058688566689220710419984397081727]
Chad Williams
Chad Williams 2020 年 2 月 26 日
Yes those are the outputs.

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeLogical についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by