Is there a function where the inputs are indices and the outputs are vectors with a value of 1 of that index and the remainder?

1 ビュー (過去 30 日間)
I am finding a function (named func, here).
If I type the following code
y = func(10, [3, 5, 1]);
then I get the following result
y = [1; 0; 1; 0; 1; 0; 0; 0; 0; 0];
The vector y is a vector with size of 10 by 1, in which the third, fifth, and first elements are one, but the rest are all zero.
Actually, I am using now the following code:
a = [3, 5, 1];
y = zeros(10,1);
y(a) = 1;
I want to use an internal function!!
  1 件のコメント
Walter Roberson
Walter Roberson 2020 年 2 月 20 日
You can construct expressions that create it without an explicit temporary variable, but they will be longer and less efficient than what you have now.


回答 (1 件)

Siriniharika Katukam
Siriniharika Katukam 2020 年 2 月 25 日
The procedure you followed seems to be a better way of doing it.


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