Is there a function where the inputs are indices and the outputs are vectors with a value of 1 of that index and the remainder?

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I am finding a function (named func, here).
If I type the following code
y = func(10, [3, 5, 1]);
then I get the following result
y = [1; 0; 1; 0; 1; 0; 0; 0; 0; 0];
The vector y is a vector with size of 10 by 1, in which the third, fifth, and first elements are one, but the rest are all zero.
Actually, I am using now the following code:
a = [3, 5, 1];
y = zeros(10,1);
y(a) = 1;
I want to use an internal function!!
  1 件のコメント
Walter Roberson
Walter Roberson 2020 年 2 月 20 日
You can construct expressions that create it without an explicit temporary variable, but they will be longer and less efficient than what you have now.

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回答 (1 件)

Siriniharika Katukam
Siriniharika Katukam 2020 年 2 月 25 日
The procedure you followed seems to be a better way of doing it.

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