Sorting matrix while removing zero values and keeping track of index at the same time.

11 ビュー (過去 30 日間)
This is after sorting but with zero values as well.
[a,ind] = sort(totalAmplitude);
bb = [a;ind]';
I want to eliminate the zero values along with its index value as well.
I tried this but this is messing up my original index as well. The index very much needed for me.
[total_amp_temp,index] = sort(nonzeros(totalAmplitude));
ccd = [total_amp_temp index];
I have attached MATFILE as well.

採用された回答

CalebJones
CalebJones 2020 年 2 月 11 日
[a,ind] = sort(totalAmplitude);
bb = [a;ind]';
check = find(bb == 0);
bb(check,:) = [];

その他の回答 (1 件)

Bhaskar R
Bhaskar R 2020 年 2 月 11 日
totalAmplitude(ind == 0)=[];
  1 件のコメント
CalebJones
CalebJones 2020 年 2 月 11 日
I need to keep a track of original index as well.
The index is the most important thing for me, since I'll be using the index for comparision later.

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