problem with the min function or the 1.8509e+007 ??

Hello everybody I have a vector with three input values so this is how my vector is :
F=[ss(60,57) ;ss(13,57) ;ss(14,57)]
F(1)
ans =
18471736
>> F(2)
ans =
1.8509e+007
>> F(3)
ans =
23963413
So i called the min function as this : [C,I]=min(F); >> C
C =
18471736
>> I
I =
1
Does 18471736 inf to 1.8509e+007

 採用された回答

Matt Fig
Matt Fig 2012 年 10 月 11 日

1 投票

There is no problem that I can see.
Yes, 1.847e7 is less than 1.851e7 and 2.396e7. Why would you expect anything else?

5 件のコメント

Mariem Harmassi
Mariem Harmassi 2012 年 10 月 11 日
This is the three values 18471736,1.8509e+007,23963413 but what about the 'e' number ??
Matt Fig
Matt Fig 2012 年 10 月 11 日
The 'e' in 1.8509e+007 is short for '10^'. This is called scientific notation.
Mariem Harmassi
Mariem Harmassi 2012 年 10 月 11 日
1.8509e+007 this notation is equivalent to 1.8509 * 10^007 ??
Walter Roberson
Walter Roberson 2012 年 10 月 11 日
Yes.
Matt Fig
Matt Fig 2012 年 10 月 11 日
As you can check:
1.2345678e7 - 1234567
ans =
0

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その他の回答 (1 件)

Walter Roberson
Walter Roberson 2012 年 10 月 11 日

0 投票

Yes. 1.8509e+007 is approximately 18509000

4 件のコメント

Mariem Harmassi
Mariem Harmassi 2012 年 10 月 11 日
編集済み: Mariem Harmassi 2012 年 10 月 11 日
its impossible cauz the three number are 3 by one dissimilarties between face images so The second one is the same person as the one compared to it so logically the second value must be the minimum
Matt Fig
Matt Fig 2012 年 10 月 11 日
編集済み: Matt Fig 2012 年 10 月 11 日
Mariem, I would venture to guess that you have just learned that MATLAB, like any other language, does exactly what you tell it to do, not what you want it to do.
Mariem Harmassi
Mariem Harmassi 2012 年 10 月 11 日
Thank u Matt , i know this it means that i should analyse the code there is an error not this one but perhaps another :/
Mariem Harmassi
Mariem Harmassi 2012 年 10 月 11 日
Don't underestimate human stupidity especially the one executed by machine ;ppp I am searching for this stupidity ordered :p

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