How to replace a rectangle with another rectangle?

1 回表示 (過去 30 日間)
Kirsten Moons
Kirsten Moons 2020 年 1 月 29 日
編集済み: Ridwan Alam 2020 年 1 月 30 日
(Or change the properties of the first rectangle)
I had 2 ideas of how to replace the rectangle, but both don't work. But here they are:
Idea 1:
r = findobj('FaceColor', [0.2 0.2 0.7])
r.FaceColor = [0.2 0.2 0.2]
Idea 2:
r = rectangle(findobj('FaceColor', [0.2 0.2 0.7]))
r.FaceColor = [0.2 0.2 0.2]
Idea 3:
r = findobj('FaceColor', [0.2 0.2 0.7])
rectangle('Position',r.Position,'LineWidth',1, 'FaceColor', [0.2 0.2 0.7])
I think you can't story a rectangle in a variable but I'm not sure and don't know how to do it otherwise. I want to change the facecolor of the rectangle with the facecolor [0.2 0.2 0.7].
  2 件のコメント
Walter Roberson
Walter Roberson 2020 年 1 月 30 日
The form in Idea 1 worked when I tried it, if the goal is to change the color of an existing rectangle without creating a new one.
Kirsten Moons
Kirsten Moons 2020 年 1 月 30 日
Okay, thank you for your feedback. Then I don't know why it doesn't work for me.

サインインしてコメントする。

回答 (1 件)

Ridwan Alam
Ridwan Alam 2020 年 1 月 30 日
編集済み: Ridwan Alam 2020 年 1 月 30 日
I tried this, it worked for me:
r = rectangle('FaceColor', [0.2 0.2 0.7]);
r.FaceColor = [0.2 0.2 0.2];
  2 件のコメント
Kirsten Moons
Kirsten Moons 2020 年 1 月 30 日
I dont know the position of the rectangle, thats why I use findobj.
Ridwan Alam
Ridwan Alam 2020 年 1 月 30 日
編集済み: Ridwan Alam 2020 年 1 月 30 日
Even this worked:
r = rectangle('FaceColor', [0.2 0.2 0.7]); % created the rectangle
r1 = findobj('FaceColor', [0.2 0.2 0.7]); % finds the rectangle handle
r1.FaceColor = [0.2 0.2 0.2]; % change rectangle property using handle
Please let me know which part is not working for you.
Btw, if the rectangle doesn't exist, findobj() returns an empty handle.

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeGraphics Object Programming についてさらに検索

製品


リリース

R2019b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by