create a matrix from matrix with zeros elements

12 ビュー (過去 30 日間)
Ali Tawfik
Ali Tawfik 2020 年 1 月 24 日
回答済み: Sindar 2020 年 1 月 29 日
I have a matrix obtained
A=[ 1 2 3 4;5 6 7 8;9 10 11 12; 13 14 15 16];
So I just would like to obtain another matrix but with some indexs (or elements ) and the rest is zeros
So I need the output matrix to be
O=[ 1 2 0 0 ;2 1 0 0 ;0 0 6 8;0 0 8 16]
So can anyone advise me with the best way ?
Thanks,
  2 件のコメント
Sindar
Sindar 2020 年 1 月 24 日
what is the logic of which elements are zero, and what value the non-zero ones take?
Ali Tawfik
Ali Tawfik 2020 年 1 月 27 日
Hi Sindar,
Thanks for your prompt reply.
Well ,I try to explain you more,
I had already a matrix, and I wanna create a new matrix based on matrix obtained earlier, then assign zeros in the matrix with some elements from the first matrix,
For example:
x=[1 2 3 4 5 6 ;
7 8 9 10 11 12;
13 14 15 16 17 18;
19 20 21 22 23 24;
25 26 27 28 29 30;
31 32 33 34 35 36]
Then, I wanna create Y as the following:
Y=[x(1,1) x(1,4) 0 0;
x(1,4) x(4,4) 0 0;
0 0 x(3,3) x(6,3);
0 0 x(6,3) x(6,6)]
I created zeros(4) so I have the new matrix, my question is how to assign some elements to the new matrix to create Y ???
Thanks,

サインインしてコメントする。

回答 (2 件)

Spencer Chen
Spencer Chen 2020 年 1 月 24 日
You can create a new matrix of the same size:
B = zeros(size(A));
Then assign non-zero data in B.
Blessings,
Spencer
  1 件のコメント
Ali Tawfik
Ali Tawfik 2020 年 1 月 27 日
Hi Spencer,
Thanks for your prompt reply.
I meant, I had already a matrix, and I wanna create a new matrix based on matrix obtained earlier, then assign zeros in the matrix with some elements from the first matrix,
For example:
x=[1 2 3 4 5 6 ;
7 8 9 10 11 12;
13 14 15 16 17 18;
19 20 21 22 23 24;
25 26 27 28 29 30;
31 32 33 34 35 36]
Then, I wanna create Y as the following:
Y=[x(1,1) x(1,4) 0 0;
x(1,4) x(4,4) 0 0;
0 0 x(3,3) x(6,3);
0 0 x(6,3) x(6,6)]
I created zeros(4) so I have the new matrix, my question is how to assign some elements to the new matrix to create Y ???
Thanks,

サインインしてコメントする。


Sindar
Sindar 2020 年 1 月 29 日
I still don't quite see the pattern, but you can insert elements manually:
x=[1 2 3 4 5 6 ;
7 8 9 10 11 12;
13 14 15 16 17 18;
19 20 21 22 23 24;
25 26 27 28 29 30;
31 32 33 34 35 36];
Y = zeros(4);
Y(1,1) = x(1,1);
Y(1,2) = x(1,4);
Y(2,1) = x(1,4);
Y(2,2) = x(4,4);
Y(3,3) = x(3,3);
Y(3,4) = x(6,3);
Y(4,3) = x(6,3);
Y(4,4) = x(6,6);
% or
Y = zeros(4);
Y(1:2,1:2) = [x(1,1) x(1,4) ; x(1,4) x(4,4)];
Y(3:4,3:4) = [x(3,3) x(6,3) ; x(6,3) x(6,6)];

カテゴリ

Help Center および File ExchangeResizing and Reshaping Matrices についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by