HEEELP : Index in position 2 is invalid. Array indices must be positive integers or logical values. !!!! why???

Hello, this is my code as you can see;

while i wrote the FOR part, matlab gives me this error. PLEASE HELP ME

opticaxis=[];
center=(length(y))/2;
for i=1:length(lambda)
    opticaxis(i,:)=E_z(:,center,i)'/(max(E_z(:,center,i)));
end
mesh(x/(1e-6),lambda/(1e-6),opticaxis)
view(2)
colormap jet
ax = gca;
ax.YDir = 'normal'
title('GRIN with Plane Wave')
xlabel('x(um)')
ylabel('\lambda(um)')

Answer 1

[Steven Lord]

center=(length(y))/2;
for i=1:length(lambda)
    
    opticaxis(i,:)=E_z(:,center,i)'/(max(E_z(:,center,i)));
    
end

If y is a vector with an odd number of elements (as an example let's say y has 3 elements) you're asking for an element of E_z that doesn't exist (in the 3 element example, you're asking for elements in the 1.5th column of E_z.)

If y is not a vector, you probably shouldn't be using length. Use size and ask for the size of y in a specified dimension.

Answer 2

[AdamG2013468]

Your for loop index is:

for i = 0:length(lambda)

Within your for loop you are attempting to create a new variable "opticaxis". You cannot define the opticaxis(0,:) point during the first index of your for loop. Try replacing your starting index value with a 1 insted of 0 (example below). This may not solve your problem just yet, but should get you closer. Also, what is the value of length(lambda)?

for i = 1:length(lambda)

[ezgi ünlü]

hello, thanks for your answer, i already write for i = 1:length(lambda) but yes, it is not solve my problem as you said. lambda is variant number, not constant about between 2.5 and 5. lambda is defined in the file.