How to add code in each cell of the GUI table?

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Dale Janry Serrano 2020 年 1 月 17 日

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https://jp.mathworks.com/matlabcentral/answers/500679-how-to-add-code-in-each-cell-of-the-gui-table

コメント済み: Walter Roberson 2020 年 1 月 19 日

Hi guys I am working a secant method with GUI and I am a total beginner in matlab. I want to ask if it is possible to add code/formula in each cell of the table in GUI? What I want to happen is to automatically solve the linear equation after I press the 'Calculate' push button and the data will be shown on the table below. The picture of the gui is attached here, thanks

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Dale Janry Serrano 2020 年 1 月 18 日

MATLAB Online で開く

Thank you Mohammad Sami! It works. However, I still have another problem. An error was occurring in the table, I think it is because it cannot process the formula of x2 since it finds the f(x0) and f(x1) first and then going back to x2 then to f(x2). I assumed that was the problem because the table is working when a constant was given to x2. Also, how can I be able to put another data to the second row of the table in case I was able to make the first row works? Thanks!!

% --- CALCULATE ----
function calculate_Callback(hObject, eventdata, handles)
x0 = str2double(get(handles.editx0,'String'));
x1 = str2double(get(handles.editx1,'String'));
x = str2double(get(handles.editx,'String'));
x22 = str2double(get(handles.editx22,'String'));
x3 = str2double(get(handles.editx3,'String'));
K = str2double(get(handles.editK,'String'));
con = str2double(get(handles.condition,'String'));
x2 = x1 - f(x1)*((x1-x0)/(f(x1)-f(x0)));
f(x0) = x3*(x0^3)+x22*(x0^2)+x*(x0)+K;
f(x1) = x3*(x1^3)+x22*(x1^2)+x*(x1)+K;
f(x2) = x3*(x2^3)+x22*(x2^2)+x*(x2)+K;
condition = str2double(get(handles.condition,'String'));
set(handles.uitable1, 'data', {x0, x1, x2, f(x0), f(x1), f(x2)});

Walter Roberson 2020 年 1 月 18 日

MATLAB Online で開く

f(x0) = x3*(x0^3)+x22*(x0^2)+x*(x0)+K;

You need to decide whether you are defining a formula, or if you are indexing. In order to define a formula, the following must be true:

The part in () on the left hand side must resolve to a symbolic variable
The symbolic variable should appear on the right hand side
You should only have one assignment with that same name on the left hand side, unless you are deliberately changing the formula. For example it is not possible to define f(0) in one assignment and f(x) in another assignment in order to define the formula under different circumstances: you only get one formula statement and it must define the answer under all circumstances

If you are indexing, the following must be true:

The part in () on the left hand side must resolve to positive integers or to logical values
the right hand side must resolve to the same number of values as the part in () on the right hand side, except that in the case where the left hand side is non-scalar, the right hand side may be scalar

x0 = str2double(get(handles.editx0,'String'));

That is going to be a numeric value, and there is no certainty that it is going to be positive integer. Therefore

f(x0) = x3*(x0^3)+x22*(x0^2)+x*(x0)+K;

is very likely to be an error. You need something more like,

f0 = x3*(x0^3)+x22*(x0^2)+x*(x0)+K;
f1 = x3*(x1^3)+x22*(x1^2)+x*(x1)+K;
f2 = x3*(x2^3)+x22*(x2^2)+x*(x2)+K;
condition = str2double(get(handles.condition,'String'));
set(handles.uitable1, 'data', {x0, x1, x2, f0, f1, f2});

Dale Janry Serrano 2020 年 1 月 19 日

MATLAB Online で開く

Hi Walter Roberson, I already did what you have said and made the f(x0), f(x1) and f(x2) to f0, f1, f2. However, when I run the program and clicked the push button 'Calculate' in the GUI there is an error occurring like this.

Error in
matlab.graphics.internal.figfile.FigFile/read>@(hObject,eventdata)equationsecant('calculate_Callback',hObject,eventdata,guidata(hObject)) 
Error while evaluating UIControl Callback.

Also, the table is working when I replace the formula of x2 as a constant. I will post a photo of my gui and code here that shows that the table is working when x2 is equal to 2. Thank you btw!!