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How to get received signal at the carrier when use Phased Array ToolBox

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Chen
Chen 2020 年 1 月 13 日
コメント済み: Honglei Chen 2020 年 1 月 14 日
Hello
Following code is copied from help of phased.Collector, My questions are
  1. what is 'receivedsig' signal frequency?
  2. How to get signal at carrier freqeuncy fc, i.e. the array each element received signal at carrier?
Thanks
Chen
-----------------------------------------------------------------------
fc = 1e9;
lambda = physconst('LightSpeed')/fc;
array = phased.ULA('NumElements',4,'ElementSpacing',lambda/2);
t = linspace(0,1,1e3);
x = cos(2*pi*200*t)';
collector = phased.Collector('Sensor',array, ...
'PropagationSpeed',physconst('LightSpeed'),'Wavefront','Plane', ...
'OperatingFrequency',fc);
incidentangle = [45;10];
receivedsig = collector(x,incidentangle);

採用された回答

Chen
Chen 2020 年 1 月 14 日
Hello HTH
Many thanks for you answer!
In order to do A(t)exp(1i*2*pi*fc*t). A(t) has to sampled at fs>=2fc. Please let me know which of followings are right, or both OK.
  1. make x is (in my code above) sampled at fs=2.1*Fc, and send to collector to get 'receivedsig', and then do receivedsig.*exp(1i*2*pi*fc*t) to get carrier data.
  2. keep x is the same in the above code. get 'receivedsig' first at low-rate. then do interplation to add points in 'receivedsig' based on ts=1/(2.1*fc), after that, do receivedsig.*exp(1i*2*pi*fc*t)
Regards!
Che
  1 件のコメント
Honglei Chen
Honglei Chen 2020 年 1 月 14 日
In theory both should work. In practice the option 1 is probably better.

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その他の回答 (1 件)

Honglei Chen
Honglei Chen 2020 年 1 月 14 日
Phased Array System Toolbox models the signal as a complex baseband representation. Normally a signal occupies certain bandwidth around a carrier in the form of A(t)exp(1i*2*pi*fc*t). So the toolbox just models A(t) as if the signal were downconvereted from the carrier.
If you want to get the origianl signal, you can just do A(t)exp(1i*2*pi*fc*t). However, make sure you really need it because to accurately represent a signal at fc, you need to at lease sample at 2*fc, which could be very high.
HTH

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