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Unable to let Ringe Kutta 4 two ODE work

2 ビュー (過去 30 日間)
Wytse Petrie
Wytse Petrie 2020 年 1 月 8 日
閉鎖済み: MATLAB Answer Bot 2021 年 8 月 20 日
Hi all,
I do not understand why my ringe kutta 4 method won't work. Maybe it is a small fault.
the differential equations are:
dy1/dx = (a - alpha*y2)*y1 - W(t)*y1,
dy2/dx (-c+gamma*y1)*y2
Can please somebody help me???
clear all
close all
clc
% parameter
a = 3;
c = 3;
alpha = 2*10^(-3);
gamma = 7*10^(-3);
% define time
ti = 0;
tf = 5;
delta_t0 = 1;
t0 = ti:delta_t0:tf;
h0 = delta_t0;
N0 = ceil(tf/h0);
% define the seasonal fishing load factor
W = zeros(N0,1);
for n =1:N0
W(n,1)=fishing_load_factor(t0(n));
end
% Define functions
fy1 = @(t,y1,y2,W) (a-alpha*y2)*y1-W*y1;
fy2 = @(t,y1,y2) (-c+gamma*y1)*y2;
%initial conditions
y1(1)=600;
y2(1)=1000;
t0(1)=0;
% Update loop
for i = 1:N0
%Update time
t0(1+i)=t0(i)+h0;
% Update y1 and y2
K11 = fy1(t0(i) ,y1(i) , y2(i), fishing_load_factor(t0(i)));
K12 = fy2(t0(i) ,y1(i) , y2(i));
K21 = fy1(t0(i)+h0/2 ,y1(i)+h0/2*K11, y2(i)+h0/2*K12, fishing_load_factor(t0(i)+h0/2));
K22 = fy2(t0(i)+h0/2 ,y1(i)+h0/2*K11, y2(i)+h0/2*K12);
K31 = fy1(t0(i)+h0/2 ,y1(i)+h0/2*K21, y2(i)+h0/2*K22, fishing_load_factor(t0(i)+h0/2));
K32 = fy2(t0(i)+h0/2 ,y1(i)+h0/2*K21, y2(i)+h0/2*K22);
K41 = fy1(t0(i)+h0 ,y1(i)+h0*K31 , y2(i)+h0*K32, fishing_load_factor(t0(i)+h0));
K42 = fy2(t0(i)+h0 ,y1(i)+h0*K31 , y2(i)+h0*K32);
y1(1+i) = y1(i)+h0/6*(K11 + 2*K21 + 2*K31 + K41);
y2(1+i) = y2(i)+h0/6*(K12 + 2*K22 + 2*K32 + K42);
end

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