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How to iterate through rows of a table, such that after each iteration some computation is done and then the below row is reached?

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Raka Mukherjee
Raka Mukherjee 2020 年 1 月 8 日
コメント済み: Walter Roberson 2020 年 2 月 4 日
I have this piece of code
for ite=1:areasize
row= r(ite,:);
xmin=xCent(1,row) - size_of_cropped_img/2;
ymin=yCent(1,row) - size_of_cropped_img/2;
crop= imcrop(image,[xmin ymin size_of_cropped_img size_of_cropped_img]);
there are 15 rows which needs to be iterated one by one to get the cropped outputs.Until now only the first output has been extracted.
I would be greatly thankful if someone can assist.

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Tony Dimichele
Tony Dimichele 2020 年 1 月 9 日
Try out some nested for loops, you will be able to create a new file with
for i = 0 : 5
destinationFolder = 'D:\Results(i)\';
This isn't correct syntax and you will require the sprintf command to add the index to strings I'm pretty sure, but this should set you in the right direction.
Guillaume 2020 年 1 月 10 日
I haven't read the whole comments and understood where the question is at now. I just want to point out that:
for ite=1:areasize
is bad coding. areasize is guaranteed to be a vector of at least 2 elements (more if allarea has more than 2 dimensions), so you're passing a vector as the upper bound of a for loop. Chances are you don't know how for behaves when you pass it a vector as bounds for the loop, so if the above works it's just by luck.
The above is equivalent to:
for iter = 1:size(allarea, 1) %iterate over the ROWS of allarea
Walter Roberson
Walter Roberson 2020 年 2 月 4 日
I see that you edited your code and removed most of the statements that people were commenting on.
However in your modified code, you are still overwriting all of the variable "crop" each time through the loop.

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Andrew Janke
Andrew Janke 2020 年 1 月 31 日
To iterate over the rows of a table, use height() to see how high your index should go:
for iRow = 1:height(r)
% ... do work on r(iRow,:) ...

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