graphing a gaussian fit of data, invalid use of operator

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todd eliason
todd eliason 2020 年 1 月 7 日
コメント済み: todd eliason 2020 年 1 月 7 日
I am trying to fit a gaussian curve to some data. dmax, a, Xo, S and dmin are all 1x1 doubles. I want to have the curve centered around Xo. however when I run the code it highlights the "-Xo" and says invalid use of operator. (I am pretty new to coding)
x = xmin:0.001:xmax;
G = (1/dmax)*exp(((a*(x.-Xo)^2))/(2*S^2)) + dmin;
plot(x,G);
  2 件のコメント
Allen
Allen 2020 年 1 月 7 日
One issue with syntax that am noticing is that you have placed a dot '.' oprerator in front of your minus '-' operator which may be causing the issue. If you are trying to perform element-wise calculations on vectors or arrays, you may need to include the dot '.' operator elsewhere in your equation, but it does not work in front of minus '-' and plus '+' math operators.
If removing the dot '.' operator from the equation does not fix the problem, can you provide a screen-shot of your workspace similar too the example below? Include all variables used in the equation for G, it would help us to understand what you are needing to accomplish.
Capture.PNG
todd eliason
todd eliason 2020 年 1 月 7 日
I fixed the problem by centering my x values on zero before I use the gaussian function. So I used the ".*" operation to square it.

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KALYAN ACHARJYA
KALYAN ACHARJYA 2020 年 1 月 7 日
編集済み: KALYAN ACHARJYA 2020 年 1 月 7 日
"however when I run the code it highlights the "-Xo" and says invalid use of operator."
G = (1/dmax)*exp(((a*(x.(-Xo))^2))/(2*S^2)) + dmin;
%........................^( ).......

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