Find the index of zero in cell and put it as empty
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A={[45;101],[2;7],[5;8],0,0};
A(cell2mat(A)==0)={[]}; % I want to find zero and put in empty
A should be
A={[45;101],[2;7],[5;8],[],[]};
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Guillaume
2020 年 1 月 7 日
編集済み: Guillaume
2020 年 1 月 7 日
A(cellfun(@(x) isequal(x, 0), A)) = {[]}; %replace any cell whose content is the scalar 0 by empty
is one way.
edit: fixed code.
6 件のコメント
Guillaume
2020 年 1 月 7 日
Do'h! I knew this was simple. Thanks, Stephen. For some reason, I had it in my head that {} and {[]} were the same thing.
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