Check the status of .exe file without running it

Hello everyone

I am trying to check an .exe file exists or not.

[status,cmdout] = system('tec360.exe') 

This command works for it. But my main purpose is that, code should check ONLY the status, it should not run it.

If .exe file is exists it will open a .dat file in the tec360.exe, if it is not exists it will show an error box.

This code works for it, but it open tec360.exe two times because of [status,cmdout] = system('tec360.exe') this command.

In first opening it opens an empty tec360.exe file, when I close it, it opens tec360.exe file with "threeDOF_result_trajectory_turning.dat" file.

Is there any one to help me about this issue?

Thanks in advance!

[status,cmdout] = system('tec360.exe')
if status==0
!tec360.exe .\threeDOF_result_trajectory_turning.dat 

elseif status==1
    errordlg('tec360.exe could not found.')
 end    

Answer 1

[Walter Roberson]

exename = 'tec360.exe';
pathparts = regexp(getenv('PATH'), ';', 'split');
found = false;
for K = 1 : length(pathparts)
    if exist(fullfile(pathparts{K}, exename), 'file')
        found = true;
        break;
    end
end
if ~found
    error('I cannot find the executable "%s"', exename);
end

[Hülya Sukas]

Thanks a lot!